60=540/d^2

Solution for 60=540/d^2 equation:

60=540/d^2

We move all terms to the left:

60-(540/d^2)=0


Domain of the equation: d^2)!=0

d!=0/1

d!=0

d∈R


We get rid of parentheses

-540/d^2+60=0

We multiply all the terms by the denominator


60*d^2-540=0

We add all the numbers together, and all the variables

60d^2-540=0

a = 60; b = 0; c = -540;
Δ = b2-4ac
Δ = 02-4·60·(-540)
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{129600}=360$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-360}{2*60}=\frac{-360}{120}
=-3
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+360}{2*60}=\frac{360}{120}
=3
$